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Unformatted text preview: s ’ is needed, proceed as follows: ( i ) determine the distance c to the neutral axis corresponding to ε t =0.004 and compute the total compressive force C c produced by concrete for this case. ( ii ) Assuming that A s ’ will yield, determine the required A s ’ to provide sufficient additional compressive force C s such that equilibrium is satisfied by T = C c + C s . ( iii ) Select a pair of bars for A s ’ and check if the provided A s ’ yields at failure. ( iv ) If A s ’ yields, compute the depth of the stress block a using equilibrium ( Σ F x =0) with f s ’= f y ; if A s ’ does not yield, write the quadratic equilibrium equation in terms of c , and solve for c . Assume d ’=3 in. from the very top of the beam. Determine the nominal flexural strength M n and the strength reduction factor Φ . Use f c '=4,000 psi, f y =60,000 psi, and E s =29,000,000 psi....
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 Spring '09
 Tensile strength, strength reduction factor, nominal flexural strength, flexural strength Mn, steel area Asb

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