This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis is an unformatted preview. Sign up to view the full document.
View Full DocumentThevalingam, Donald Homework 23 Due: Mar 21 2007, midnight Inst: Eslami 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points Three particles are located in a coordinate system as shown in the figure below. The acceleration of gravity is 9 . 8 m / s 2 . The mass 8 kg is located at the origin, the mass 3 kg is located on the x coordinate, and the mass 6 kg is located on the y coordinate. x y 6 kg 8 kg 3 kg 13 m 4 m Find the distance of the center of gravity from the origin. Correct answer: 2 . 69371 m. Explanation: The center of gravity of the x and y compo- nents from the origin respectively are x c = m 0 + m 1 x 1 m + m 1 + m 2 = (3 kg) (13 m) (8 kg) + (3 kg) + (6 kg) = 2 . 29412 m and y c = m 0 + m 2 y 2 m + m 1 + m 2 = (6 kg) (4 m) (8 kg) + (3 kg) + (6 kg) = 1 . 41176 m . Then the distance of the center of gravity from the origin is d = q x 2 c + y 2 c = q (2 . 29412 m) 2 + (1 . 41176 m) 2 = 2 . 69371 m .... View Full Document
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentSOL24
SOL25
SOL26
solution_pdf hw 4
solution_pdf
tsoi exam
HW23
263_Physics ProblemsTechnical Physics
22
OLDHW24
Homework_9-solutions
Homework_9-solutions
Copyright © 2015. Course Hero, Inc.
Course Hero is not sponsored or endorsed by any college or university.