SOL27 - Thevalingam, Donald Homework 27 Due: Apr 27 2007,...

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Unformatted text preview: Thevalingam, Donald Homework 27 Due: Apr 27 2007, midnight Inst: Eslami 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points A record has an angular speed of 34 . 4 rev / min. What is its angular speed? Correct answer: 3 . 60236 rad / s. Explanation: Let : = 34 . 4 rev / min . Therefore, 1 = (34 . 4 rev / min) 2 rad rev 1 min 60 s = 3 . 60236 rad / s . 002 (part 2 of 2) 10 points Through what angle, does it rotate in 1 . 24 s? Correct answer: 4 . 46693 rad. Explanation: Let : t = 1 . 24 s . = t = (3 . 60236 rad / s) (1 . 24 s) = 4 . 46693 rad . keywords: 003 (part 1 of 2) 10 points A racing car travels on a circular track of radius 261 m. The car moves with a constant linear speed of 37 . 2 m / s. Find its angular speed. Correct answer: 0 . 142529 rad / s. Explanation: Let : v = 37 . 2 m / s and R = 261 m . The linear speed v and angular speed are related by v = R = v R = 37 . 2 m / s 261 m = . 142529 rad / s . 004 (part 2 of 2) 10 points Find the magnitude of its acceleration. Correct answer: 5 . 30207 m / s 2 . Explanation: If the car is moving at a constant speed, there is no tangential acceleration, so the ac- celeration is purely radial: a r = v 2 R = (37 . 2 m / s) 2 261 m = 5 . 30207 m / s 2 ....
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SOL27 - Thevalingam, Donald Homework 27 Due: Apr 27 2007,...

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