322af09_plq2_2_key

322af09_plq2_2_key - CHEMISTRY 3223L W W9 flmct‘c‘...

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Unformatted text preview: CHEMISTRY 3223L W W9 flmct‘c‘ 1“ 3‘08 LAB QUIZ . m KEY Lab time T.A. TOT This test comprises this sheet and three numbered pages. Tests will Apr 27 — 29, and if you in1 will be put out in the S -1- 11-: 1. (13) For the methylpentene (MP) prep from 4-$£6Ly1-2-p (cs3)2cxcszcs<omcs3 (SM), and 60% or (a)(5) Even at 90°, the water solubility of the SM is low. initially one phase. a chemical equation and <15 words. out, an arganic Layer appears in the pot 804] has increased. n this new organic layer. room T. the reaction mixture was (1) Explain, using (ii) As MPs distill although the pot T ~ 90° and [H in <15 words; reter to what is Twealymfm/ a} ([44796] [f0 00~gvatM< caft‘ovl] @“7 Led) {Ky-MAJ? A @ (Cu. W a40v€3 (b)(4) As the GC analysis showed rearranged carbocations. actually formed. is larger from the stronger acid. es among c rbocations; use <25 words total. . U} («putty/£661: flw i <(+3<'H='Ci<l/»Ch§ £9,461, ~1Mclt W] M” UL.) LL {Wow “my/l «ya/67¢ C¢r~éoc€f /( (NM 0'1 # “MN. [rm wmye {fa gum 1‘” W {fab/e “4/53 2. (4) Note the gas chromatogram of a MP mixture: The area of a peak is estimated as 'XD-h'. Tell how Kb is found, using <10 words, then draw the baseline and mark Kb on the arrowed peak. “:5” a 29%. 7a /@ b06401 (Tu/u l I! IIIIIIIIIIIII|IIIIIIIIB1II of (44 (31% {mm bmdi‘nk \————/ 7 3 entanol, 70* aq H2804: But at Explain é 5% '- £011” #3“??? lél‘égy41_ r‘/¥Q.C7 C] No) M w k/c/xww/Lénp, owz Wows/e «41‘ «f, , some of the MP5 must come from (1) Draw structures of two such MPs (ii) Explain why the rearranged MP tractign Refer to competing process- '1 l 1 5' “ll III-II—n---__. III III |l|_|ll I'! F- Illlll Iiiiiitfih- . I...--u- 1 Hana I 12 ’3 lg.“ uu "II". J... )l I] Eill‘ilr ! ma 1 (13 points this page) — 2 - (b) (4) Brz W to I, is a two-step sing reaction. Its second 1 L the ham reaction below (disregard stereochemistry): «c {WMC A)th aflmyfiqafg" “fl??3r“f”z‘?’M’ * sm‘ ( < Mw (c) (6) The "successful" reaction mixture contained initially 100 1/25 LB“? ("01‘qu we) flecv‘fod/l‘fit 1742 546/ G909" (573017}. -3- 3. (continued, 10 points on this page) /qu [ (d)(8) One can view I a III as two steps: (1) I in D cmzru as supercooled liq, Keq a 1; then (2) III scl * IIIsolid' (i)(4) At equilibrium in solution with 43.0 mmol DCM, the sum of the mole fractions of I and III a 1/5, i.e. X(I+III) a o 20 Calculate (1) mmols I+III in soln, and (2) mmol solid III obtained from 30 mmol I. (OCH 0.? 1 15...: i=5; 291le 0/ 2r "m" ~_~——- .9 U +51»: ‘9 “‘ ‘ Maw/Etta? 0‘7/ Ms W‘ ‘ “11> C) ‘ u&w«o @ L2) MM! wMfl 2 30.41) “ma/.4.“ MW! 0W M r246 (m w a) (Jami :0“! 171:1 AG a 0 and thus . 1. Taking R a 2.0 cal/mole-K, and 43a“. 20 cal'QmT), one can use (la a —R(37S + T)1n thln to calculate T for a given thln. ‘4 (C =- 1.0? (i)(3) For thin a 5, calcu at the T (Ts solution in DCM is just saturated n III (e)(6) At 102°(375 K), the mp of III, => AT”: 4.5% (< => my =(J75—éfZ)K : 3/0],Z K '3 0C (ii)(1) In <10 words, tell what thln means. MLMUUS-e) L/Igfln) a fill. (Jedi/(1y cm Mag/MIME t: (507/0).£é)u/€7 ab tyre/6M] 5m (efgsem) I 1 MC {MM ...
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322af09_plq2_2_key - CHEMISTRY 3223L W W9 flmct‘c‘...

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