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Unformatted text preview: CHAPTER 2
1. (a) 200 yd (b) 0 (c) 0 2. (a) False. The car may be slowing down, so that the direction of its acceleration is
opposite the direction of its velocity.
(b) True. If the velocity is in the direction chosen as negative, a positive acceleration
causes a decrease in speed.
(c) True. For an accelerating particle to stop at all, the velocity and acceleration must
have opposite signs, so that the speed is decreasing. If this is the case, the particle will
eventually come to rest. If the acceleration remains constant, however, the particle
must begin to move again, opposite to the direction of its original velocity. If the
particle comes to rest and then stays at rest, the acceleration has become zero at the
moment the motion stops. This is the case for a braking car—the acceleration is
negative and goes to zero as the car comes to rest. 3. The velocity-time graph (a) has a constant slope, indicating a constant acceleration, which
is represented by acceleration-time graph (e).
Graph (b) represents an object whose speed always increases, and does so at an ever
increasing rate. Thus, the acceleration must be increasing, and the acceleration-time graph
that best indicates this is (d).
Graph (c) depicts an object that first has a velocity that increases at a constant rate, which
means its acceleration is constant. The motion then changes to one at constant speed,
indicating that the acceleration of the object becomes zero. Thus, the best match to this
situation is graph (f). 4. (b). According to graph b, there are some instants in time when the object is simultaneously
at two different x-coordinates. This is physically impossible. 5. (a) The blue graph of Figure 2.14b best shows the puck’s position as a function of time. As
seen in Figure 2.14a, the distance the puck has traveled grows at an increasing rate for
approximately three time intervals, grows at a steady rate for about four time
intervals, and then grows at a diminishing rate for the last two inte...
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