notes_Chemtalk_7_answer_key_2

notes_Chemtalk_7_answer_key_2 - Chem 312 Winter 2010...

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Chem 312 Winter 2010 "Chem–Talk" #7 Key Friday, February 26, 2010 1. In class we will talk about the d–orbital splitting diagram for complexes containing six identical ligands. Upon the introduction of two different types of ligands to form the D 4h transition- metal complex below, the d–orbitals split differently. Use the Character Table below to determine which d–orbitals would be degenerate in this complex. How many d– electrons would this complex have? (NH 3 and H 2 O are both neutral ligands) Mn 3+ would have 4 d–electrons. OH 2 Mn H 3 N NH 3 OH 2 H 3 N NH 3 3+ Thus, the only remaining degenerate pair would be the (d xz , d yz ). The d–orbital splitting diagram for this molecule would be as shown below (the details of which will be described in lecture next week). This diagram is shown only for your
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edification, but was not required for your chemtalk answer to be correct. 2.
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notes_Chemtalk_7_answer_key_2 - Chem 312 Winter 2010...

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