HW10solution - superposition.-.. z zD : -" ,44...

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Homework #10 Due: April8,2009 Name 4/1n009 11:04:00 AM 1. In the circuit shown below that you solved in HW8 using mesh analysis, find the voltage vs ocross the 3 kQ resistor using Thevenin's theorem. 7? I sur-r V vo: v L/ lz'- 1" /u o 'Z^A 3L 7-l /LL 7 3L }L'Z L 3Lu V,: 2v + [\. /', 9u 7L Ur' fi v lt*- zL f t" >t- 1- 2L *-----2 -t Ir 1 kC) vo 2k{' 6V 3 koo_'. )u:z f,r^ =
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Homework #10 Due: April8,2009 4/ln009 I l:04:00 AM 2- In the circuit shown below find the current rs through the 3e resistor using
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Unformatted text preview: superposition.-.. z zD : -" ,44 z+j 5 KEY io: 4. A .A zn7 f,', D' 3v-'-z+7 In Cw'rt<l ),u 4,= /DA | f,,, t baj = 2A + 4 A + O.A 5 nn 4Q Homework #10 Due: April 9,2009 3. Repeat euestion 2 using Thevenin,s theorem. %.='?t-t, t Name 4/5n0091t:38:00 pM v, I v3 4A \- v; r v)u Vr' {b- = 3v q. = Ic-E= 4"= Z3V \" = zou't 4f. Ao-= 1.f.- 3v 70r/+q-q43/ rb= 4 I a = 4.44 2: t 23v S -n, DC 4C) 2 J-( L*r^ = L-^...
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This note was uploaded on 03/05/2010 for the course EGR 240 taught by Professor Michael,p during the Winter '08 term at Oakland University.

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HW10solution - superposition.-.. z zD : -" ,44...

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