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Unformatted text preview: In the next step when the lead nitrate solution was added to the potassium iodide solution a precipitate formed when either H2O2 or H2S were added. In part C, the goal was to determine the exact ratio of ions in a precipitate, which proved to be more difficult. My sources of error I think showed in this step because it was hard to make sure the medicine dropper was thoroughly clean before switching to a different chemical. Also there was probably some human error when I tried adding the exact amount of drops to each solution. Having said that I did get the formula of the precipitate to be PbI2. Test tube four seemed to contain the correct ratio, as a very minimal amount of precipitate had formed in the test tube. This makes the ratio of drops 1Pb: 2I. When adding drops in this ratio no ions are present in excess....
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