homework 5 - b. more than 3 of the couples have both...

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Ex 5-1 7 No the probability cannot be a negative and the sum of probabilities is not 1 10 it represents a probability distribution 19 x= 0 1 2 3 P(x) 6/15. 5/15. 3/15. 1/15. 28 BBB --> 3 boys x= 0 1 2 3 BBG --> 2 boys P(x) 1/8. 3/8. 3/8. 1/8. BGB --> 2 boys GBB --> 2 boys BGG --> 1 boy GBG --> 1 boy GGB --> 1 boy GGG --> 0 boys Ex 5-2 2 the mean =19*0.2+20*0.2+21*0.3+22*0.2+23*0.1=2.9 the variance= 425.79 20.63 .=standard deviation 7 The mean =5*0.2+6*0.25+7*0.38+8*0.10+9*0.07=6.6 the variance= 1.3 the standard deviation=1.1 18 x= 360 -99,640 P(X) 1 0 360*0.999057+-99,640*0.000943=265.70 The expected value of the policy is $ 265.70 Ex 5-3 10 a. none of the couples have both person working
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Unformatted text preview: b. more than 3 of the couples have both persons in the labor force 1 - (5,0.521,3) = 0.1249 c. Fewer than 2 of the couples have both parties working. P(0 <= x <= 1) = binomcdf(5,0.521,1) = 0.1624 15 the mean=8 the variance=7.9 Exercises 5 - 1: 7, 10, 19, 28 Exercises 5 - 2: 2, 7, 18 Exercises 5 - 3: 10, 15, 23 the standard distribution=2.8 23 10/10-3=10/7=1.4 The probability that 3 most will believe that the U.S government should take primary responsibility for e eliminating poverty is 1.4...
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This note was uploaded on 03/06/2010 for the course STRATEGY L AAB1ST taught by Professor Andersjensen during the Spring '10 term at Aarhus Universitet.

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homework 5 - b. more than 3 of the couples have both...

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