Unformatted text preview: of the oscillation? ANS Since the masses are not moving initially, the energy of the system is completely potential energy. If we find the equilibrium position of the oscillator, this will be where the potential energy is zero and the kinetic energy is maximum. Thus the difference between the initial position and the equilibrium position is the amplitude of the oscillation. tau=k theta+(m1m2)gR. Thus in equilibrium theta=(m1m2)gR/k, the magnitude of which is the amplitude...
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 Spring '08
 Walker
 Physics, Energy, Kinetic Energy, Mass, Potential Energy, equilibrium position, spring potential energy, oscillation. tau=k theta+

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