quiz12_solution - Answer Initial potential energy =1/2 k...

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A 2 kg block is pushed against a spring that has a spring constant of 500 N/m, compressing the spring by 20 cm. The block is then released, and the spring projects it along a frictionless horizontal surface and then up a frictionless incline of 45 degrees. How far does the block travel up the incline before coming (temporarily) to rest?
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Unformatted text preview: Answer: Initial potential energy =1/2 k x^2=10 J. The kinetic energy after release must therefore be also 10 J. The height at which it stops is mgh=10 J which gives h=.51 m. The distance is h/sin(th)=0.72 m....
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