Unformatted text preview: Answer: Initial potential energy =1/2 k x^2=10 J. The kinetic energy after release must therefore be also 10 J. The height at which it stops is mgh=10 J which gives h=.51 m. The distance is h/sin(th)=0.72 m....
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 Spring '08
 Walker
 Physics, Energy, Force, Friction, Kinetic Energy, Mass, Potential Energy, frictionless horizontal surface

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