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Unformatted text preview: v_x is unaltered in the air and the ball continues to spin. Therefore only the ycontribution to the translational kinetic energy is exchanged for potential energy. mgy=1/2m v_y^2=m/2(mgh/(m+I/R^2)/2) Therefore y=h/4(1+I/(mR^2))....
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 Spring '08
 Walker
 Physics, Inertia, Mass

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