Unformatted text preview: Ans: Let theta be the angle made by the lever with respect to the horizontal. Then the torque balance gives Mgd cos(theta)=F(Ld) cos(theta) or F=Mgd/(Ld). If y is the vertical distance that the force acts over, then using similar triangles: d/h = L/y so y=Lh/d Then the work done by the force is W=Fy = MgdLh/((Ld)d) = MgLh/(Ld)...
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 Spring '08
 Walker
 Physics, Energy, Force, Mass, lever

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