Practice_midterm_2_Solutions

Practice_midterm_2_Solutions - direction as the magnetic...

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Solutions Practice Midterm 2 Problem1
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Problem 2
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Problem 3
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Problem 5 Problem 1. Part A. One rotation requires time T . s x s m x m x v r T 16 6 10 10 3 . 1 10 4 . 2 ) 10 5 . 0 ( 2 2 - - = = = π Hz x T f 15 10 6 . 7 1 = = ( 1 - = s Hz ) Part B. A x Hz x C x qf dt dq I 3 15 19 10 2 . 1 ) 10 6 . 7 )( 10 6 . 1 ( - - = = = = Part C. CCW Part D. B a a a × = μ τ , A I a a = k Am x k m x A x ˆ 10 4 . 9 ˆ ) 10 5 . 0 ( ) 10 2 . 1 ( 2 24 2 10 3 - - - = = ) ˆ ( 10 4 . 9 ) ˆ 10 ( ) ˆ 10 4 . 9 ( 2 28 4 2 24 i T Am x j T k Am x - = × = - - - Part E. 0 = - = B PE a a ) 90 ( ° = Θ Part F. This is an intermediate value. The minimum value should be negative. Part G. The minimum potential energy can be achieved by orienting the area vector in the same
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Unformatted text preview: direction as the magnetic field. This would require the current loop to travel counter-clockwise perpendicular to the plane of the page as viewed from above....
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This note was uploaded on 03/06/2010 for the course PHYSICS 201 taught by Professor Walker during the Spring '08 term at Wisconsin.

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Practice_midterm_2_Solutions - direction as the magnetic...

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