Unformatted text preview: 2-16 Part III.- Desion ofproductson systems ’I‘MiliH ES—IE
Hes-lead solution 'l'flHIiH 55-" [ii
Evaluation of cell 1-»1 Warehouse Note that the revised solution has a total cost that is $51] less than
the previous solution {$2,3CIU versus $2,350}, which is exactly.r equal
to the cell evaluation value times the number of units shifted:
—5 a ll] units = —$5tl. Is this the optimum? IElnce again, we must evaluate each empty.r
cell to determine if further improvements are possible. Recall that
it is necessary to check to see that there are enough completed
cells to allour all empty cells to have evaluation paths. Thus, s+c—1=s+4h1=s Since there are six completed cells, the second round of cell evalua- tions can proceed. The cell paths and their values are shown in Tables 53—16 to 53-21. Since all are either zero or positive, this
solution is the optimum. Warehouse ...
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- Spring '09
- shakroh
- Math
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