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Unformatted text preview:  (1 /x )2  < , or equivalently 1 / 2 < x < 1 / 2 + , x 6 = 1 / 2 implies 2 < 1 /x < 2 + . (b) Find a that veries the required condition if = 0 . 1 . To get 1 . 9 < 1 /x < 2 . 1, need 1 / (2 . 1) < x < 1 / (1 . 9), so can be any positive number less than or equal to the smaller of 1 / 21 / (2 . 1) = 1 / 42 and 1 / (1 . 9)1 / 2 = 1 / 38, that is, any < 1 / 42. For example, = . 02 would do. 1...
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This note was uploaded on 03/08/2010 for the course MATH 1A taught by Professor Wilkening during the Fall '08 term at University of California, Berkeley.
 Fall '08
 WILKENING
 Calculus

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