Quiz 5 - y =-2 x + y x + 2 y , so y = 0 when y =-2 x ....

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Prof. Haiman Math 1A—Calculus Fall, 2006 Quiz 5 solutions—version A Name Student ID Number 1. Differentiate the following functions of x . (a) (2 x 3 - 5 x ) 8 8(2 x 3 - 5 x ) 7 (6 x 2 - 5) (b) sin - 1 ( x ) 1 2 p x (1 - x ) 2. Find the points on the ellipse x 2 + xy + y 2 = 3 where the tangent line is horizontal. Implicit differentiation gives
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Unformatted text preview: y =-2 x + y x + 2 y , so y = 0 when y =-2 x . Substitute y =-2 x into the equation of the ellipse to get 3 x 2 = 3, so x = 1. Using y =-2 x again, nd two solutions: (1 ,-2) and (-1 , 2). 1...
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