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Exp12 - Chem 1310-Experiment 12 KINETICS OF CRYSTAL VIOLET...

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Chem 1310-Experiment 12 KINETICS OF CRYSTAL VIOLET Data & Results -Excel (80 pts total ) NaOH (1ml) 0.1M 0.1M 0.1M time Run 1 @ 20 Abs ln Abs 1/Abs 0 0.32 -1.14 3.12 20 0.35 -1.05 2.87 40 0.34 -1.09 2.98 60 0.32 -1.13 3.09 80 0.31 -1.16 3.2 100 0.3 -1.2 3.32 120 0.29 -1.24 3.44 140 0.28 -1.27 3.56 160 0.27 -1.3 3.68 180 0.26 -1.34 3.82 200 0.25 -1.37 3.95 220 0.24 -1.41 4.11 240 0.23 -1.45 4.26 260 0.23 -1.48 4.41 280 0.22 -1.52 4.58 300 0.21 -1.56 4.75 320 0.2 -1.6 4.96 340 0.19 -1.64 5.18 360 0.19 -1.67 5.33 380 0.18 -1.71 5.52 400 0.18 -1.73 5.67 420 0.17 -1.77 5.85 440 0.17 -1.8 6.04 460 0.16 -1.83 6.24 480 0.16 -1.86 6.45 500 0.15 -1.89 6.63 520 0.15 -1.93 6.86 540 0.14 -1.96 7.07 560 0.14 -1.99 7.33 580 0.13 -2.02 7.56 600 0.13 -2.05 7.75 Reaction Order, m 1 #1. Finding m, order number with respect to [CV] and k obs (40 PTS total) (21pts-7 pts per plot including slope & R 2 ) Plot #1 Abs (Y) vs. time in sec (X) Plot #2 Ln Abs (Y) vs. time in sec (X) Plot #3 1/Abs (Y) vs. time in sec (X) 0 100 200 300 400 500 600 700 0 0.1 0.2 0.3 0.4 f(x) = 0x + 0.33 R² = 0.98 Abs vs Time Time (s) Absorbance (565 nm) 0 100 200 300 400 500 600 700 -2.5 -2 -1.5 -1 -0.5 0 f(x) = 0x - 1.04 R² = 1 Ln(Abs) vs TIme Time (s) Ln(Absobance) 0 100 200 300 400 500 600 700 0 2 4 6 8 10 f(x) = 0.01x + 2.48 R² = 0.98 1/Abs vs Time Time (s) 1/Absorbance
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0.1M 0.05M 0.01M 0.01M 0.01M Run 2 @ 20 Run 1 @ 20 TIME (s) Abs Abs ln (Abs) ln (Abs) TIME(s) Abs Abs Abs ln (Abs) ln (Abs) ln (Abs) 0 0.32 0.25 -1.14 -1.39 0 0.3 0.2 0.23 -1.2 -1.61 -1.48 20 0.35 0.31 -1.05 -1.16 10 0.3 0.24 0.23 -1.22 -1.44 -1.45 40 0.34 0.3 -1.09 -1.19 20 0.29 0.22 0.21 -1.24 -1.52 -1.54 60 0.32 0.3 -1.13 -1.21 30 0.28 0.21 0.2 -1.28 -1.58
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