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Unformatted text preview: high. Since high to low is just a half cycle the period of oscillation from high to high has to be multiplied by 2. Therefore, T = 2 * Dinv giving us Dinv = T/2. (ii) if Dinv = 10ns, n = 21, f = 1/T, T = 2 * Dinv. Therefore f = 2.38 MHz c) The Signals at P, Q, R, S are part of a larger system which we have already proved as periodic because of its oscillation, therefore these signals have to be periodic too. The time period it takes for one gate to switch its output from H to H or L to L is just the overall time period which we have measured to be 58 ns. Signals P & R have the opposite value of A whereas signals Q & S retain the same value....
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- Fall '08