1)
R=n(t+1)/n(t)
N(t)=
60, n(t+1)/n(t)= 2.4
Therefore, the population abundance at the next time step is:
60*2.4= 144
N(t)=400, n(t+1)/n(t)= .8 Therefore, the population abundance at the next time step is:
400*.8=320
Based on the observed growth rates, it shows that as N(t) increases, the observed growth rate
decreases.
From the data provided it can be assumed that as the population size (N) increases
and space becomes more crowded, the population growth rate (R) declines due to the decrease in
the resources available to support the bigger population density.
2) The graph shown in figure 2, in my opinion, represents deterministic chaos. Chaos model can
be defined by fluctuations from high levels to lower levels of abundance.
The data shows wild
population fluctuations from high to low without any change in environmental conditions.
3) From exercise 3.5 I’ve obtained the following tables presented on the next page. I can
conclude that at low population levels I would use constant rate harvesting. When we compare
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 Spring '08
 GINZBURG
 Ecology, Demography, Population Ecology, World population, constant rate harvesting

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