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Homework 3 Bio 356

# Homework 3 Bio 356 - 1 R=n(t 1/n(t N(t)= 60 n(t 1/n(t)= 2.4...

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1) R=n(t+1)/n(t) N(t)= 60, n(t+1)/n(t)= 2.4 Therefore, the population abundance at the next time step is: 60*2.4= 144 N(t)=400, n(t+1)/n(t)= .8 Therefore, the population abundance at the next time step is: 400*.8=320 Based on the observed growth rates, it shows that as N(t) increases, the observed growth rate decreases. From the data provided it can be assumed that as the population size (N) increases and space becomes more crowded, the population growth rate (R) declines due to the decrease in the resources available to support the bigger population density. 2) The graph shown in figure 2, in my opinion, represents deterministic chaos. Chaos model can be defined by fluctuations from high levels to lower levels of abundance. The data shows wild population fluctuations from high to low without any change in environmental conditions. 3) From exercise 3.5 I’ve obtained the following tables presented on the next page. I can conclude that at low population levels I would use constant rate harvesting. When we compare

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Homework 3 Bio 356 - 1 R=n(t 1/n(t N(t)= 60 n(t 1/n(t)= 2.4...

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