{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

CHAPTER 1 - 4

# CHAPTER 1 - 4 - 30 ,000mi(a 40mi/h,wehave...

This preview shows pages 1–2. Sign up to view the full content.

30. We assume the distance from Beijing to Paris is 10,000 mi. ( a ) If we assume that today’s race car can travel for an extended period at an average speed of  40 mi/h, we have time = [(10,000 mi)/(40 mi/h)](1 day/24 h) ˜         10 days . ( b ) If we assume that in 1906 a race car could travel for an extended period at an average speed of  5 mi/h, we have time = [(10,000 mi)/(5 mi/h)](1 day/24 h) ˜         80 days . 31. We assume that each dentist sees 10 patients/day, 5 days/wk for 48 wk/yr, for a total number of  visits of N visits  = (10 visits/day)(5 days/wk)(48 wk/yr) ˜ 2400 visits/yr. We assume that each person sees a dentist 2 times/yr. ( a ) We assume that the population of San Francisco is 700,000.  We let the units lead us to the answer: N  = (700,000)(2 visits/yr)/(2400 visits/yr) ˜        600 dentists .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

CHAPTER 1 - 4 - 30 ,000mi(a 40mi/h,wehave...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online