CHAPTER 2 - 1 -...

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CHAPTER 2 - Describing Motion: Kinematics in One Dimension 1. We find the time from average speed =  d / t ; 15 km/h = (75 km)/ t  , which gives        t  = 5.0 h . 2. We find the average speed from average speed =  d / t  = (280 km)/(3.2 h) =        88 km/h . 3. We find the distance traveled from average speed =  d / t ; (110 km/h)/(3600 s/h) =  d /(2.0 s), which gives        d = 6.1 × 10 –2  km = 61 m . 4. We find the average velocity from æ  = ( x 2  –  x 1 )/( t 2  –  t 1 ) = (– 4.2 cm – 3.4 cm)/(6.1 s – 3.0 s) =        – 2.5 cm/s (toward –  x ) . 5. We find the average velocity from æ  = ( x 2  –  x 1 )/( t 2  –  t 1 ) = (8.5 cm – 3.4 cm)/[4.5 s – (– 2.0 s)] =        0.78 cm/s (toward +  x ) . Because we do not know the total distance traveled, we cannot calculate the average speed. 6.
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This note was uploaded on 03/08/2010 for the course PHYSICS 7A/7B taught by Professor All during the Fall '08 term at Berkeley.

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CHAPTER 2 - 1 -...

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