CHAPTER 2 - 4 - 40 v (m/s) 30 20 10 0 0 10 20 30 40 50 60...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
0 10 20 30 40 50 60 70 80 90 100 110 120 t  (s) 0 10 20 30 40 v  (m/s) 5th gear 3rd gear 2nd gear 1st gear 4th gear 0 10 20 30 40 t  (s) 0 10 20 30 40 50 22. ( a ) The maximum velocity is indicated by the highest point, which occurs at        t  = 50 s . ( b ) Constant velocity is indicated by a horizontal slope, which occurs from        t  = 90 s to 107 s . ( c ) Constant acceleration is indicated by a straight line, which occurs from        t  = 0 to 30 s, and  t  = 90 s to 107 s . ( d ) The maximum acceleration is when the slope is greatest:        t  = 75 s . 23. We find the acceleration (assumed to be constant) from v 2  =  v 0 2  + 2 a ( x 2  –  x 1 );  0 = [(100 km/h)/(3.6 ks/h)] 2  + 2 a (55 m), which gives        = – 7.0 m/s 2 . The number of  g ’s is N  =  | a | / g  = (7.0 m/s 2 )/(9.80 m/s 2 ) =        
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

CHAPTER 2 - 4 - 40 v (m/s) 30 20 10 0 0 10 20 30 40 50 60...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online