CHAPTER 3 - 2 - θ V V x V y x y x ( a ) C = A + B A B C x...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: θ V V x V y x y x ( a ) C = A + B A B C x ( b ) C = A – B A – B C x ( c ) C = B – A – A B C 6. ( a ) V 1 x = – 6.0, V 1 y = 0 ; V 2 x = V 2 cos 45° = 4.5 cos 45° = 3.18 = 3.2 , V 2 y = V 2 sin 45° = 4.5 sin 45° = 3.18 = 3.2 . ( b ) For the components of the sum we have R x = V 1 x + V 2 x = – 6.0 + 3.18 = – 2.82; R y = V 1 y + V 2 y = 0 + 3.18 = 3.18. We find the resultant from R = ( R x 2 + R y 2 ) 1/2 = [(– 2.82) 2 + (3.18) 2 ] 1/2 = 4.3 ; tan θ = R y / R x = (3.18)/(2.82) = 1.13, which gives θ = 48° above – x-axis . Note that we have used the magnitude of R x for the angle indicated on the diagram. 7. ( a ) ( b ) For the components of the vector we have V x = – V cos θ = – 14.3 cos 34.8° = = – 14....
View Full Document

This note was uploaded on 03/08/2010 for the course PHYSICS 7A/7B taught by Professor All during the Fall '08 term at Berkeley.

Page1 / 2

CHAPTER 3 - 2 - θ V V x V y x y x ( a ) C = A + B A B C x...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online