CHAPTER 3 - 4 - 12(a R R x =A B C x x x y...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
12.( a ) For the components we have R x A x  +  B x  +  C x   = 44.0 cos 28.0 °  – 26.5 cos 56.0 °  + 0 =         24.0 ; R y A y  +  B y  +  C y = 44.0 sin 28.0 °  + 26.5 sin 56.0 °  – 31.0 =         11.6 . ( b ) We find the resultant from R  = ( R x 2  +  R y 2 ) 1/2  = [(24.0) 2  + (11.6) 2 ] 1/2   =          26.7 ; tan  θ  =  R y / R x  = (11.6)/(24.0) = 0.483, which gives          θ  = 25.8 °  above +  x -axis 13. ( a ) For the components we have R x B x  –  A x   = – 26.5 cos 56.0 °  – 44.0 cos 28.0 °  = – 53.7; R y B y  –  A y = 26.5 sin 56.0 °  – 44.0 sin 28.0 °  = 1.3. We find the resultant from R  = ( R x 2  +  R y 2 ) 1/2  = [(– 53.7) 2  + (1.3) 2 ] 1/2   =          53.7 ; tan  θ  =  R y / R x  = (1.3)/(53.7) = 0.0245, which gives 
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern