CHAPTER 3 - 11

# CHAPTER 3 - 11 - x h θ y v O 30 We choose a coordinate...

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Unformatted text preview: x h θ y v O 30. We choose a coordinate system with the origin at the release point, with x horizontal and y vertical, with the positive direction down. We find the time of fall from the vertical displacement: y = y + v y t + ! a y t 2 ; 9.0 m = 0 + 0 + ! (9.80 m/s 2 ) t 2 , which gives t = 1.35 s. The horizontal motion will have constant velocity. We find the initial speed from x = x + v x t ; 8.5 m = 0 + v (1.35 s), which gives v = 6.3 m/s . 31. We find the time of flight from the vertical displacement: y = y + v y t + ! a y t 2 ; 0 = 0 + (18.0 m/s)(sin 32.0°) t + ! (– 9.80 m/s 2 ) t 2 , which gives t = 0, 1.95 s. The ball is kicked at t = 0, so the football hits the ground 1.95 s later. 32. We choose a coordinate system with the origin at the release point, with 32....
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CHAPTER 3 - 11 - x h θ y v O 30 We choose a coordinate...

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