CHAPTER 3 - 21 - x y z v D North East h D 1 D 2 D 3 up 70....

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Unformatted text preview: x y z v D North East h D 1 D 2 D 3 up 70. If v PW is the velocity of the airplane with respect to the wind, v PG the velocity of the airplane with respect to the ground, and v WG the velocity of the wind with respect to the ground, then v PG = v PW + v WG , as shown in the diagram. We have two unknowns: v PG and (or ). If we use the law of sines for the vector triangle, we have v PW /sin (90 + ) = v WG /sin , or sin = ( v WG / v PW )sin (90 + ) = [(120 km/h)/(680 km/h)] sin (90.0 + 35.0) = 0.145, or = 8.31. Thus we have = + = 8.31 + 35.0 = 43.3 N of E . 71. If v CG is the velocity of the car with respect to the ground, v MG the velocity of the motorcycle with respect to the ground, and v MC the velocity of the motorcycle with respect to the car, then...
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CHAPTER 3 - 21 - x y z v D North East h D 1 D 2 D 3 up 70....

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