CHAPTER 4 - 1 - CHAPTER4Dynamics:NewtonsLawsofMotion 1....

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CHAPTER 4 - Dynamics: Newton’s Laws of Motion 1. We convert the units: #  lb = (0.25 lb)(4.45 N/lb) ˜ 1 N. 2. If we select the bike and rider as the object, we apply Newton’s second law to find the mass: ? ma ;   255 N =  m (2.20 m/s 2 ), which gives        m  = 116 kg . 3. We apply Newton’s second law to the object: ? ma ;   F  = (7.0 × 10 –3  kg)(10,000)(9.80 m/s 2 ) =        6.9 × 10 2  N . 4. Without friction, the only horizontal force is the tension.  We apply Newton’s second law to the car: ? ma ;   F T  = (1250 kg)(1.30 m/s 2 ) =        1.63 × 10 3  N . 5. We find the weight from the value of  g . ( a ) Earth: F G  =  mg  = (58 kg)(9.80 m/s 2 ) =        5.7 × 10 2  N . ( b ) Moon: F G  =  mg  = (58 kg)(1.7 m/s 2 ) =        99 N . ( c
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CHAPTER 4 - 1 - CHAPTER4Dynamics:NewtonsLawsofMotion 1....

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