CHAPTER 4 - 11 - m 1 g m 2 g y F N F T x y F T a a This is...

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Unformatted text preview: m 1 g m 2 g y F N F T x y F T a a This is also F 32 (Newtons third law). ( e ) When we use the given values, we get a = F /( m 1 + m 2 + m 3 ) = (96.0 N)/(12.0 kg + 12.0 kg + 12.0 kg) = 2.67 m/s 2 . F net1 = m 1 a = (12.0 kg)(2.67 m/s 2 ) = 32.0 N. F net2 = m 2 a = (12.0 kg)(2.67 m/s 2 ) = 32.0 N. F net3 = m 3 a = (12.0 kg)(2.67 m/s 2 ) = 32.0 N. Because the blocks have the same mass and the same acceleration, we expect F net1 = F net2 = F net3 = 32.0 N . For the forces between the blocks we have F 21 = F 12 = F m 1 a = 96.0 N (12.0 kg)(2.67 m/s 2 ) = 64.0 N . F 32 = F 23 = F m 1 a m 2 a = 96.0 N (12.0 kg)(2.67 m/s 2 ) (12.0 kg)(2.67 m/s 2 ) = 32.0 N . 47. ( a ) ( b ) If the system is released from rest, the blocks will...
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CHAPTER 4 - 11 - m 1 g m 2 g y F N F T x y F T a a This is...

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