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Unformatted text preview: * * 2 * 2 2 1 1 = − − − h N L N h N L N k k µ (2) Here I’ve already used the relation 1 1 N f k = and 2 2 N f k = . From equation (1), 1 2 N Mg N − = . Then plug it into equation (2), ( ) ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + − = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ − h L N Mg h L N h L N k k k 2 * 2 * 2 * 1 2 1 Therefore, Mg L h L N k 2 2 1 + = & Mg L h L N k 2 2 2 − = . At the same time, Mg L h L f k k 2 2 1 + = & Mg L h L f k 2 2 2 − = b) The critical condition for the overturning to happen is the normal force N 2 becomes zero. 2 2 2 = − = Mg L h L N k , Then k h L = 2 . The condition to prevent that from happening is k h L > 2 ....
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This note was uploaded on 03/09/2010 for the course PHYSICS 7A taught by Professor Lanzara during the Fall '08 term at Berkeley.
 Fall '08
 Lanzara
 Physics, Acceleration, Center Of Mass, Mass

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