Unformatted text preview: df = 16, t = 2.33 p = 0.016 ( or 0.018 if they are using the t table from the text) Fail to reject null hypothesis at α = 0.01. TwoSample TTest and CI Sample N Mean StDev SE Mean 1 8 1.710 0.530 0.19 2 10 2.530 0.870 0.28 Difference = mu (1)  mu (2) Estimate for difference: 0.820 95% upper bound for difference: 0.207 TTest of difference = 0 (vs <): TValue = 2.33 PValue = 0.016 DF = 16 Both use Pooled StDev = 0.7407 8.40 this problem should be analyzed using a paired ttest, so the issue of equal variances is irrelevant....
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This note was uploaded on 03/09/2010 for the course STAT 350 taught by Professor Staff during the Spring '08 term at Purdue.
 Spring '08
 Staff
 Statistics, Variance

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