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# HW8 - STAT 350 Homework#8 CORRECTED SOLUTION Due at the...

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STAT 350 – Homework #8 CORRECTED SOLUTION (4/27/08) Due: at the beginning of class on Monday, April 7, 2008 Text Exercises Chapter 9 problems #36 1 , 38(a,b) 1,2 Chapter 10 problems #8 1,2 1 be sure to give a full ANOVA table to accompany your answer! 2 you may do the analysis in SAS 9.36 Source df SS MS F p Assessor 2 11.7 5.85 1.82813 0.221882 House (block) 4 113.5 28.375 8.86719 0.004892 Error 8 25.6 3.2 Total 14 150.8 a. There is no significant difference among the assessors ( p -value = 0.221882) b. The house effect was significant, thus it was warranted as a blocking factor.

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9.38 Source df SS MS F p Grade 2 90754.66667 45377.33333 393.45 <.0001 Species 2 2216.00000 1108.00000 9.61 0.0297 Error 4 461.33333 115.33333 Total 8 93432.00000 a. Yes, there is a significant difference in the three species of wood ( p = 0.0297) b. Yes, there is a significant difference in the three grades of wood ( p < 0.0001) SAS data prob938; input grade \$ species \$ bend; cards; ss doug 370 g2 doug 381 g3 doug 165 ss hem 386 g2 hem 390 g3 hem 182 ss spf 430 g2 spf 405 g3 spf 195 ; run ; proc anova data=prob938; class grade species; model bend= grade species; run ; The ANOVA Procedure Dependent Variable: bend Sum of Source DF Squares Mean Square F Value Pr > F Model 4 92970.66667 23242.66667 201.53 <.0001 Error 4 461.33333 115.33333 Corrected Total 8 93432.00000 R-Square Coeff Var Root MSE bend Mean 0.995062 3.328307 10.73934 322.6667 Source DF Anova SS Mean Square F Value Pr > F grade 2 90754.66667 45377.33333 393.45 <.0001 species 2 2216.00000 1108.00000 9.61 0.0297
10.8

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HW8 - STAT 350 Homework#8 CORRECTED SOLUTION Due at the...

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