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# 4 - Version 101/ABCBB ict 02 Turner(58120 This print-out...

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Version 101/ABCBB – ict 02 – Turner – (58120) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A toy cannon fires a 0 . 133 kg shell with initial velocity v i = 8 . 1 m / s in the direction θ = 44 above the horizontal. Δ x Δ h 8 . 1 m / s 44 Δ y y The shell’s trajectory curves downward be- cause of gravity, so at the time t = 0 . 308 s the shell is below the straight line by some vertical distance Δ h . Find this distance Δ h in the absence of air resistance. The acceleration of gravity is 9 . 8 m / s 2 . 1. 0.464834 2. 0.211994 3. 1.41828 4. 0.308705 5. 1.20548 6. 0.523952 7. 0.944333 8. 1.02336 9. 0.737666 10. 2.99647 Correct answer: 0 . 464834 m. Explanation: In the absence of gravity, the shell would fly along the straight line at constant velocity: ˆ x = t v i cos θ , ˆ y = t v i sin θ . The gravity does not affect the x coordinate of the shell, but it does pull its y coordinate at constant downward acceleration a y = - g , hence x = t v i cos θ, y = t v i sin θ - g t 2 2 .

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