Mos exam 2 03

Mos exam 2 03 - for brass, and 10x106 psi for aluminum. The...

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Unformatted text preview: for brass, and 10x106 psi for aluminum. The beam is kip-in about a horizontal axis. a) Find the maximum stress in each of the three metals. b) Find the radius of curvature (p) of the beam. c) Would p increase, decrease, or interchanged? (You do not need to do any calculations to explain your answer.) lWW“)?(Zn—Wanna 7': (u)(.s>’+(m(-s)m‘f ’ ‘1 ,0957 7; z 2.3M? +3654 = Q-IH’ In ‘ (Iz,aw)(l-z€) r . - : €51 - f V t n _. 4/Immpm - a; ‘0) 2"“, 4. Pg], . " z, .7 - . ‘ brass: 02 = W : 4,170 ’05; she! = 0: =8) (12.0»)(ac) M = 91/3 5/ 146’? > I l’ - 'M __ _ 541 " loll/o‘)(z.1é&) > f m ’ I It ‘ ( —-‘ '- n l to El [21000 f 6&2: or If ’ i ' I ‘ ’\CWS‘€ L a) Mglwnsmj 60155 W a/mmm «MAM n I ntor 'I'Aa Sada?” S», )9 New“ mare“: . A steel beam with a W200 X 52 cross section is fixed at one end and resists an axial load of 500 RN and an unknown horizontal load P at the end of the cantilever. The two loads act through the centroid of the section. The yield stress of the material is 350 MPa. The self- weight of the section may be neglected. What is the allowable load P that can be applied to the section, using a factor of safety of 2.5 against yield? (See following page for properties of the section.) ‘1 y 753 Appendix C. Properties of Rolled-Steel Shapes T? (SI Units) 11 X X Continued from page 751 J— '“’ W Shapes Y (Wide-Flange Shapes) ' L I)!!! 9.“ W310 X 143 18200 323 107 13600 3] l 74 9480 310 81.2 531 77.3 23.4 228 49.7 38.7 4940 32.7 4180 313 23.8 3040 l .92 37.6 2 l .4 67 8580 58 7420 252 49. l 6250 247 44.8 5720 ' 18.8 l85 350.3 15.1 150. 49.2 v 3.5» o * 1 ‘ '; ' --: : . 91. was; Wl30 X 28.l 3580 [3| “56 55.2 ~ 23.8 30l0 127 I39 54.] 3.” 49.0 32.] w100x19.3 2480 106 90.0 43.9 l.6l '31.3 25.5 ‘i'A Wide-flange shape is designated by the letter W followed by the nominal depth in millimeters and the mass in kilograms per meicn 3.81 59.5 32.6 * k W'flknflifl 13.2111. mmmmnmwm ,.4« r 1 ww «(v - u 5, 3. A 6 foot long ski is designed to distribute the weight of the skier on the snow. The skier’s weight can be assumed as a point load at the middle of the ski. If the skier (including all gear) causes a load of 180 lb on each ski, and the distribution of force (upward) of the snow on the ski can be written as w(x) = —i-§[x— <x—1.5~>‘ — < x—4.5 >‘], where x is in feet from the leading edge of the ski, and wo is a constant with units of pounds per foot: a) Determine the value for we. b) Sketch w(x). c) Determine the expressions for shear and bending moment using singularity functions. d) Sketch the shear and bending moment diagrams, and identify the location and magnitude of maximum bending moment. 4. The beam shown consists of two 4” x 1” boards, which are nailed together as shown. The nails have a diameter of V4” and an allowable stress of 20ksi. Determine: ,a) the maximum shear force? M 4M6 W b) the maximum shear stress in the section? . c) the nail spacing to resist the maximum shear? d) if the nail spacing is varied to reflect the shear force at each section, how many nails are required" between the point loads? * - P=2kips firm: _ b ‘ 3ft —>l«—’ i sit—4+~ ~3ft ,QH'R&.:P=1\L~P‘ ' . 3 2g" 3(114X3)‘+61uXo.s) .Lmlfvww I91 yes ' ' 8 ‘ 4"——-l ' I = P75 L g VG - ‘ (l WNW - I; .(%P+(Hx3vp.7s)L+(t+_)t_nl3 I +- QOJS'O 25>z‘ -.~. Is-rz act I _ ‘ ‘ .15) =S-28fn3 0mm ‘ls Isl x37 ‘ (W: its”) {0581163 wa ') : c9 mamas) =5 a: V9 dag) = 0-55 L/m ’ I 1847 ...
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Mos exam 2 03 - for brass, and 10x106 psi for aluminum. The...

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