ass17 - SOLUTIONS, ASSIGNMENT 17 26.38. IDENTIFY:An...

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SOLUTIONS, ASSIGNMENT 17 26.38. I DENTIFY : An uncharged capacitor is placed into a circuit. Apply the loop rule at each time. S ET U P : The voltage across a capacitor is / C V q C = . E XECUTE : (a) At the instant the circuit is completed, there is no voltage over the capacitor, since it has no charge stored. (b) Since 0 C V = , the full battery voltage appears across the resistor 125 V. R V = = E (c) There is no charge on the capacitor. (d) The current through the resistor is total 125 V 0.0167 A. 7500 i R = = = E (e) After a long time has passed the full battery voltage is across the capacitor and 0 i = . The voltage across the capacitor balances the emf: 125 V. C V = The voltage across the resister is zero. The capacitor’s charge is 6 4 (4.60 10 F) (125 V) 5.75 10 C. C q CV - - = = × = × The current in the circuit is zero. E VALUATE : The current in the circuit starts at 0.0167 A and decays to zero. The charge on the capacitor starts at zero and rises to 4 5.75 10 C q - = × . 26.41.
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This note was uploaded on 03/11/2010 for the course PHYSICS 1523 taught by Professor Dfs during the Fall '10 term at Dallas.

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ass17 - SOLUTIONS, ASSIGNMENT 17 26.38. IDENTIFY:An...

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