ass23 - SOLUTIONS Assignment 23 28.40 = IDENTIFY B nI0 = 0...

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SOLUTIONS, Assignment 23 28.40. I DENTIFY : 0 0 μ NI Bμ nI L = = S ET U P : 0.150 m L = E XECUTE : 0 (600) (8.00 A) 0.0402 T (0.150 m) μ B = = E VALUATE : The field near the center of the solenoid is independent of the radius of the solenoid, as long as the radius is much less than the length. 28.41. (a) I DENTIFY and S ET U P : The magnetic field near the center of a long solenoid is given by Eq.(28.23), 0 . B nI μ = E XECUTE : Turns per unit length 7 0 0.0270 T 1790 (4 10 T m/A)(12.0 A) B n I π - = = = × turns/m (b) (1790 turns/m)(0.400 m) 716 turns N nL = = = Each turn of radius R has a length 2 R of wire. The total length of wire required is 2 (2 ) (716)(2 )(1.40 10 m) 63.0 m. N R - = × = E VALUATE : A large length of wire is required. Due to the length of wire the solenoid will have appreciable resistance. 28.44. I DENTIFY : Example 28.10 shows that outside a toroidal solenoid there is no magnetic field and inside it the magnetic field is given by 0 . 2
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ass23 - SOLUTIONS Assignment 23 28.40 = IDENTIFY B nI0 = 0...

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