Homework04

# Homework04 - johnson(rj6247 – hw 4 – Opyrchal –(121014 1 This print-out should have 10 questions Multiple-choice questions may continue on

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Unformatted text preview: johnson (rj6247) – hw 4 – Opyrchal – (121014) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Two charges are located along the x-axis. One has a charge of 6 . 2 μ C, and the second has a charge of − 3 . 5 μ C. The Coulomb constant is k e = 8 . 98755 × 10 9 N m 2 / C 2 . The acceleration of gravity is 9 . 81 m / s 2 . If the electrical potential energy associated with the pair of charges is − 4 . 7 × 10- 2 J, what is the distance between the charges? Correct answer: 4 . 1507 m. Explanation: Let : q 1 = 6 . 2 μ C , q 2 = − 3 . 5 μ C , U electric = − 4 . 7 × 10- 2 J , and k e = 8 . 99 × 10 9 N · m 2 / C 2 . U electric = k e q 1 q 2 r r = k e q 1 q 2 U electric = (8 . 99 × 10 9 N · m 2 / C 2 ) × (6 . 2 × 10- 6 C)( − 3 . 5 × 10- 6 C) − 4 . 7 × 10- 2 J = 4 . 1507 m . 002 (part 1 of 2) 10.0 points An object with a charge 9 C and a mass . 1 kg accelerates from rest to a speed of 17 m / s. Calculate the kinetic energy gained. Correct answer: 14 . 45 J. Explanation: Let : m = 0 . 1 kg and v = 17 m / s . The kinetic energy is K = 1 2 mv 2 = 1 2 (0 . 1 kg) (17 m / s) 2 = 14 . 45 J . 003 (part 2 of 2) 10.0 points Through how large a potential difference did the object fall? Correct answer: 1 . 60556 V. Explanation: Let : q = 9 C . The potential difference is Δ V = K q = 14 . 45 J 9 C = 1 . 60556 V . 004 10.0 points A uniform electric field of magnitude 276 V / m is directed in the positive x-direction. Sup- pose a 12 μ C charge moves from the origin to point A at the coordinates, (37 cm, 52 cm)....
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## This note was uploaded on 03/11/2010 for the course PHYS 121 taught by Professor Opyrchal during the Spring '08 term at NJIT.

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Homework04 - johnson(rj6247 – hw 4 – Opyrchal –(121014 1 This print-out should have 10 questions Multiple-choice questions may continue on

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