Homework15

# Homework15 - johnson(rj6247 hw 14 Opyrchal(121014 This...

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johnson (rj6247) – hw 14 – Opyrchal – (121014) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points In a certain series RLC circuit, the rms cur- rent is 12 . 7 A , the rms voltage is 244 V and the current leads the voltage by 37 . What is the total resistance of the circuit? Correct answer: 15 . 3439 Ω. Explanation: Let : I rms = 12 . 7 A , V rms = 244 V , and φ = - 37 . The average power delivered by the generator is dissipated as heat in the resistor: P av = I rms V rms cos φ = (12 . 7 A) (244 V) cos( - 37 ) = 2474 . 81 W , and the power dissipated in the resistor is P av = I 2 rms R , so the resistance is R = P av I 2 rms = 2474 . 81 W (12 . 7 A) 2 = 15 . 3439 Ω . 002 (part 2 of 2) 10.0 points Calculate the reactance X L - X C of the cir- cuit. Correct answer: - 11 . 5624 Ω. Explanation: For the reactance, tan φ = X L - X C R X L - X C = R tan φ = (15 . 3439 Ω) tan( - 37 ) = - 11 . 5624 Ω . 003 (part 1 of 2) 10.0 points In a series RLC circuit, the resistance is 29 Ω, the capacitance is 79 μ F and the inductance is 40 mH. The AC generator provides an rms

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