Phys121-1sol

# Phys121-1sol - Anderson Matthew – Homework 1 – Due...

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Unformatted text preview: Anderson, Matthew – Homework 1 – Due: Jan 30 2008, 10:00 am – Inst: Vitaly 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 2) 15 points Consider three force vectors ~ F 1 , ~ F 2 , and ~ F 3 . The vector ~ F 1 has magnitude F 1 = 51 N and direction θ 1 = 51 ◦ ; the vector ~ F 2 has mag- nitude F 2 = 26 N and direction θ 2 =- 29 ◦ ; and the vector ~ F 3 has magnitude F 3 = 11 N and direction θ 3 = 110 ◦ . All the direction an- gles θ are measured from the positive x axis: counter-clockwise for θ > 0 and clockwise for θ < 0. What is the magnitude F of the net force vector ~ F = ~ F 1 + ~ F 2 + ~ F 3 ? Correct answer: 63 . 2827 N. Explanation: In components, each force vector is F 1 ,x = F 1 × cos θ 1 = 32 . 0953 N , F 1 ,y = F 1 × sin θ 1 = 39 . 6344 N , F 2 ,x = F 2 × cos θ 2 = 22 . 7401 N , F 2 ,y = F 2 × sin θ 2 =- 12 . 6051 N , F 3 ,x = F 3 × cos θ 3 =- 3 . 76222 N , F 3 ,y = F 3 × sin θ 3 = 10 . 3366 N , and therefore the net force is F x = F 1 ,x + F 2 ,x + F 3 ,x = 51 . 0732 N , F y = F 1 ,y + F 2 ,y + F 3 ,y = 37 . 366 N ....
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## This note was uploaded on 03/11/2010 for the course PHYS 121 taught by Professor Opyrchal during the Spring '08 term at NJIT.

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Phys121-1sol - Anderson Matthew – Homework 1 – Due...

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