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Unformatted text preview: Tw = Ta= Ra= .75 Tp= 305 Rp=120 Service Time Factor Tp=4m, S=4, Tp/s = 4/4 = 1 Utilization Factor U= 45/60 = .75 (Sqroot 2* (S+1))-1 (square root 2 *5) -1 = 2.162 (.75)>2.162 / (.25) = .537/.25 = 2.15 Variation factor 1 Tw = 1*2.15 *1= 2.15 min (129 seconds) What is the average number of customers at QN? T= 2.15 + 4 = 6.15 minutes ; I=RaT I= .75* 6.15 = 4.6 customers How long would a customer spend at QuickNacho if one more server were added? S=5 U=.75/5*.25=.6 Service Time Factor 4/5 = .8m Ut Factor ( An office server can be accessed by remote or direct connections. During peak time, queries arrive through remote every 10 seconds and through direct every 5 seconds both with a SD of 2s; the server can handle an average of 25 queries per minute with a SD of 3s About how much time on the average does a query wait for response? Approximately how many queries will be waiting to be processed, on average?...
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- Fall '09
- Standard Deviation, Mean, Service time factor