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Unformatted text preview: 1 KE = mv 2 2 W = F ⋅ ∆x m kg ⋅ = J s
2 C inelastic ≡ if _ m1 >>>>> m2 _ v f = vi C inelastic ≡ if _ m1 <<<<<<< m2 _ v f = C elastic ≡ m1v1 m2 1 1 1 1 2 2 m1v12,i + m2 v 2,i = m1v12, f + m2 v 2, f 2 2 2 2 h Mgh − ( m + M ) ⋅ g ⋅ W = F ⋅ cos θ ⋅ ∆x 2 W = ∆KE pulleysystem ≡ v sameheight = 1 (m + M ) ≤ 1F = ∑ W 2 Mgh − mgh F & S ≠ parallel = W = F ⋅ cos θ ⋅ ∆x pulleysystem ≡ v Malmost @ ground = 1 ⋅(m + M ) x2 2 F ≠ cons. = W = ∫ f ( x)dx x1 v 2 _ above _ eqn. from pulleysystem ≡ d heightafterMstops = Ff 2⋅ g µk = Fn WJ Fs = −kx P= = = Watts A ⋅ B = AB cos θ T S PE g = mgh KE i + PEi = KE f + PE f PE elastic = 1 ⋅ k ⋅ x2 2 p = mv ∫ ∆P
i f momentum = ∫ F ⋅ ∆t
i f Pf − Pi = ∫ F ⋅ ∆t = I C inelastic ≡ m1v1 + m2 v 2 = ( m1 + m2 ) ⋅ v f C inelastic ≡ v f = m1v1 + m2 v 2 m1 + m2 ...
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This note was uploaded on 03/12/2010 for the course PHY 110 taught by Professor Su during the Fall '08 term at Illinois State.
 Fall '08
 SU
 Physics, Heat

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