Chapter 30b - Exam 2 Results avg. 13.5 October 26, 2009 Ch....

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Exam 2 Results avg. 13.5 Ch. 30: Induction and Inductance - Part B 1 October 26, 2009
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Exam 2 Results Ch. 30: Induction and Inductance - Part B 2 October 26, 2009
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Chapter 30: Induction and Inductance Review of induction. Eddy currents. EMF by rotation. HITT question. q Induced electric fields. ductors and inductance. Inductors and inductance. Ch. 30: Induction and Inductance - Part B 3 October 26, 2009
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Faraday’s Law of Induction An emf is induced when the magnetic field flux changes with time, its value equal to the rate at hich the magnetic field flux changes with time : B d -emf - agnetic field flux which the magnetic field flux changes with time : Faraday’s  N dt B magnetic field flux - number of turns N law B BdA   Magnetic flux. Surface defined by a conducting loop. a vector of magnitude A nd direction of the A Ch. 30: Induction and Inductance - Part B 4 October 26, 2009 is a vector of magnitude dA and direction of the area normal. dA
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How To Create and EMF? B d dt     cos B BdA B dA Change the magnitude of the magnetic field B within the coil. Change the area of the coil or the portion of the coil that lies within the magnetic field (e.g. expand or shrink the coil, or move it in and out of the field). Change the angle between the direction of the agnetic field and the plane of the coil (e g by Ch. 30: Induction and Inductance - Part B 5 October 26, 2009 magnetic field and the plane of the coil (e.g. by rotating the coil).
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Faraday’s Law and Lenz’s Law Use Faraday’s law to get the magnitude of the induced emf. B d dt Use Lenz’s law to get the direction of the induced mf and current emf and current. B d The minus sign symbolizes  dt Lenz’s law. he induced emf opposes the magnetic flux change! Ch. 30: Induction and Inductance - Part B 6 October 26, 2009 The induced emf opposes the magnetic flux change!
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Motional EMF A conducting loop is moving out of a magnetic field at a constant velocity v . pool the loop at a constant velocity To pool the loop at a constant velocity, we need to apply a constant force oing positive work to oppose the doing positive work to oppose the magnetic force created in the loop. Mechanical work is transferred to thermal energy in the loop. BLv i  22 2 2 BLv PF vi R  BLv Ch. 30: Induction and Inductance - Part B 7 October 26, 2009 R R
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Eddy Currents A solid conducting plate is moving out of a magnetic field at a constant velocity v .
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This note was uploaded on 03/12/2010 for the course PHY PHY taught by Professor Mueller during the Spring '09 term at University of Florida.

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Chapter 30b - Exam 2 Results avg. 13.5 October 26, 2009 Ch....

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