98aMTReviewPPT - Bio 98A Midterm Review Marilyn edit Click...

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Click to edit Master subtitle style Bio 98A Midterm Review Marilyn Le
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Take a few minutes to do as many problems from the packet as you can. On lecture 2 outline the chart should be For # 26 C, it should be 6 mM and 4 mM not mmol. Answers (this ppt) will be posted. You must play some of the animations for the answers to come up. HA (protonated) A- (deprotonated) Amino group, Lys, Arg, His +1 0 Carboxyl group, CYSTEINE , Tyr, Glu, Asp 0 -1
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Put the following biochemical interactions in order of their strength: hydrogen bonds, disulfide bonds, ionic bonds, interactions between lipid hydrocarbon tails A. Disulfide > ionic > H-bonds ~ interactions b/t lipid hydrocarbon tails B. Ionic > disulfide > H-bonds > interactions b/t lipid hydrocarbon tails C. Disulfide > H-bonds > Ionic > interactions b/t lipid hydrocarbon tails
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Put the following biochemical interactions in order of their strength: hydrogen bonds, disulfide bonds, ionic bonds, interactions between lipid hydrocarbon tails A. Disulfide > ionic > H-bonds ≈ interactions b/t lipid hydrocarbon tails B. Ionic > disulfide > H-bonds > interactions b/t lipid hydrocarbon tails C. Disulfide > H-bonds > Ionic > interactions b/t lipid hydrocarbon tails
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Find the pH of 2 mL of 0.35 M of NaH2PO4 and 1 mL of 0.15 M of Na2HPO4 (pKa of NaH2PO4 = 6.86) NaH2PO4 = 2 mL x 0.35 M = 0.7 mmol Na2HPO4 = 1 mL x 0.15 M = 0.15 mmol pH = pKa + log [A-] / [HA] = 6.86 + log (0.15 / 0.7) = 6.19
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You WANT pH= 6 pH = pKa + log [A-]/[HA] 6 = 5.2 + log [A-]/[HA] = 86.3% A- and 13.7% HA You HAVE acid 13.7% acid = 86.3% acetate 20 mmol acid X mmol acetate = 126 mmol acetate If have 20mmol of acetic acid, how much acetate should you add to get a pH of 6? pKa = 5.2
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Sketch the titration curve of lysine pKa values amino = 9.1 carboxyl = 2.2 R group = 10.5
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NH3+ - F A L H L C COOH pKa 9.13 -- -- -- 6.0 -- 8.18 1.96 Charge +1 -- -- -- +0.5 0 -1 pH << pKa ..: protonated l +1 pH = pKa .: 50% protonated & + 0.5 .: 50% deprotonated & 0 pH >> pKa ..: deprotonated l -1 Net: +0.5 Find the net charge of the peptide FALHLC at pH 6 pH << pKa ..: protonated l 0
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HA (protonated) A- (deprotonated) Amino group, Lys, Arg, His +1 0 Carboxyl group, CYSTEINE , Tyr, Glu, Asp 0 -1 *it was wrong on my review outline; just remember if you look it up on the chart and it has a pKa it is an ionizable group.
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If two cysteines made a disulfide bond, would changes in pH affect the R group? A. Yes, cysteine has an ionizble R group whether in a disulfide bond or not B. Yes, but only one of the cysteines will be affected by pH C. No, cysteines in a disulfide bond do not have hydrogens and therefore will not be affected by pH D. None of the above
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Cys I S I S I Cys When two Cys make a disulfide bond, there is NO ionizable H Cys I S H Free Cys has an ionizable H C. No, cysteines in a disulfide bond do not have hydrogens and therefore will not be affected by pH
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You have three proteins: protein A made up mostly
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This note was uploaded on 03/15/2010 for the course BIO SCI 97 07777 taught by Professor Yi during the Spring '10 term at UC Irvine.

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98aMTReviewPPT - Bio 98A Midterm Review Marilyn edit Click...

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