recitation_12

recitation_12 - Solution to the problem in recitation 12...

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Solution to the problem in recitation 12 Known: Composition of ideal gas mixture on molar basis; operation parameters of turbine. Find: Mass fractions; molar flow rates of mixture components Change in molar enthalpy Power output of turbine. Schematic and Given Data: i n i CO 2 0.125 H 2 O 0.125 N 2 0.75 m = 10 kg/s P1 = 22 bar, T1 = 1700K, p2 = 1 bar Assumptions: 1. The overall mixture acts as an ideal gas, mixture composition remains constant, the state of each component is defined by the temperature and its partial pressure. 2. Issentropic process in turbine. 3. the control volume of turbine is at steady state 4. Constant specific heats 5. No change in KE and PE Analysis: a) For gas mixture, base the solution on 1 kmol of mixture. i n i y i M i m i =n i M i mf i CO 2 125 12.5% 44 5500 19.1% H 2 O 125 12.5% 18 2250 7.8% N 2 750 75% 28 21000 73.1% 1000 M = 28.75 28750 100% Total molar flow rate M m n = = 10 (kg/s) * (1/28.75) (kmol/kg) = 0.348 kmol/s For each component, 2 2 CO CO
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recitation_12 - Solution to the problem in recitation 12...

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