solutions to HA 5_6

General Chemistry (4th Edition)

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Unformatted text preview: . _ -1 turm+renu+nit11 "~[mn1—[n111—‘3'3IS —— ”I [[113 + ma + malts? 41313 + [1131. = cps—1m) = are Titus. the resculyed sltear stress fur this [Di ijl— [1T1] slip system is Twill-[1T1] = = [4.0 MPaII [chs [00”) ens [54.T"II] = [4.0 MFaII [0] [0.5T0] = 0 MPa And. finally. it is necessary tn detemtine tlte yalue sf 4: far the [i0Ti—[iT1] slip system —that is. tlte angle between the directimt at the applied stress. [[00]. and the nnrntal tn the 00le plane—i.e.- the [101'] directinn. Again using Eguatinn 7.0 1 m [1] + [nun — nit—n . [[03 + m3 —[I113][r0E + m3 — [—03] ?'[100]—[i0T] = “'5— Here. as 1arith the [i 10]— [iTi ] slip system ahnye. the yalue sf [2» is 45". 1arhich again leads tn T RI; lUTJ-l 1T 1] = [4.0 MPaII [cns[45°}l cc.s[54.T°i] = [4.0 h-lPai [0.00TII[CI.5’."S]I = 1.03 hlPa [hj The ntnst faynred slip system[sj is [are] the nnelfisjl that has [have] the largest TE yalue. Ruth [1030— [iTi] and [iDT] —[1Ti] slip systems are ntnst faynred since they has the same TR [1.03 h-IPa]. 1arhich is greater thanthe rRyalue fnr [0ii] —[iT1] Ma. 0 IylPajI. ...
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