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3.18

General Chemistry (4th Edition)

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Unformatted text preview: 3.13 Thi-a problem calls for us to compute the atomic radio-3 for Mg. In order to do this. we must me Equation 3.5. as well a5. the expre-a-ziou which relates the atomic radio-3 to the unit cell 't'ohune for HE'P: flout Problem 3J5 it “a; ahowu that t}: = a a) w? 111 this case C= 1.6343. but. for HEP. a = 253'. which meme. that l}: = Elecaemjomnfi = {1.5:4][1:~fi}e‘ And fl'om Equation 3.5. the density i3 equal to “Ah-1g l‘h-‘fl [1.62:1]{12453F a; And: whine for Rfroro the above equation leads to the following: R 'l - 1.-'3 = I141 IE i_(1.624]|:121.‘n'§}p.-"£__5L l.-"3 _ I'fi atoma-"tmit eel] 544.31 a-"mol! :| _ {1.624)(l?fi}{l.?4g-’em3:|l:5.fl23 >: m3 atom-mat} =1.rsu x 1&3 em= 0.150 11:11 ...
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