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3.59

General Chemistry (4th Edition)

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Unformatted text preview: 3.39 Fi'cnm the table. ct—ii'c-n has a EEC crystal stiuctui'e and an atomic radius cf 3112.41 nin L'sing Equatinn 3.3 the lattice parameter: a: may he ccurnputed as fell-tins: 43? 4- .134-1 «F3 33 How. the d: 11 intemlanar spacing may he deteiinined using Equatien 3.14 as find: similarly for d: -_1 _ 3.3333 nnl 5r. =4-— "1 3:233 -{1)'i + (13* {a = [1.1111] nm 3.51 (a) From the data given in the pi'nhlein and iealizing that 33.993 = 28. the interplanai' spacing for the [.31 1) set if planes f'c-r Nb icna}r he ccmputed using Equation 3.13 as fell-nus: n3. (13:0.1333 nnt] as =—=—= 3.1343 311 33333 33.333: 1”“ Flynn 1- .' a _ {b} In cinder tn ccnqmte the atcnnc radius we must first detennine the lattice parameter. s. using Equatinn 3.1-4, and then R flc-rn Equaticin 3.3 since Eh has. a EEC crystal stiucture. Iherefaie, a= 3'11- ;233 — {131 + {1]3=(u.13¢3 um]{~3'3}=c-.33-:3ti nin :— . Anti. fi'c-nl Equation 3.3 33: 3:433 =33.333333343331331 3 =a.1423 um ...
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