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# Test1Solution - Solution of ECE 300 Test 1 F09 1 Let V s =...

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Unformatted text preview: Solution of ECE 300 Test 1 F09 1. Let V s = 10V, R = 20 Ω , I = − 2A . Find the numerical power delivered to R and Z . (The voltage across each of these three elements connected in parallel is the same.) V s R Z I P R = V 2 / R = 10V ( ) 2 / 20 Ω = 5 W , P z = − 10V × − 2A ( ) ⎡ ⎣ ⎤ ⎦ = 20W 2. Below is a graph of the charge that has passed from left to right through a wire versus time. Find the numerical value of the current flowing from left to right in the wire at these times. (a) t = 1 ms The current is the time derivative of the charge. At this time the slope of the charge versus time is 10 μ C/2 ms = 5 mA . (b) t = 3 ms At this time the slope of the charge versus time is 0 μ C/2 ms = 0 mA . (c) t = 5 ms At this time the slope of the charge versus time is − 10 μ C/4 ms = − 2.5 mA . t (ms) q( t ) ( μ C) 2 4 8 10 3. Below is a graph of current flowing left to right through a wire versus time. Find the numerical value of the charge that has passed through the wire from left to right at these times assuming that no charge has...
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Test1Solution - Solution of ECE 300 Test 1 F09 1 Let V s =...

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