{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Case Study Appendix

# Case Study Appendix - degree of freedom = 1.960 CI...

This preview shows pages 1–6. Sign up to view the full content.

Case Study Appendix A: B:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
C: D:
E:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
F: CI = (X-bar apple – X-bar east ) ± t √ (S X-bar apple 2 + S X-bar east 2 ) The formula to find S X-bar is: [S X-bar = (S apple / √ (n) ) 2 [S X-bar apple = 10.0256], [S X-bar east = 14.0810] In order to find t, we must use the t chart. The t value for 95% confidence with an infinite degree of freedom = 1.960. CI = (104.8175 – 87.6751) ± 1.960 √ (10.0256 + 14.0810) CI = (7.5192 , 26.7657) G: CI = (Slope of the regression line, b) ± t of (108-2) (S b ) The formula to find S b is: [S b = (S e /S x √ (n-1)) [S e = 24.44] [S b =.507] In order to find t, we must use the t chart. The t value for 95% confidence with an infinite

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: degree of freedom = 1.960. CI = -2.22-1.960*.507<0, -2.22+1.96*.507<0 :CI does not contain null hypothesis, zero. H: Correl. Coeff:-0.0 858 6 Slope:-0.0 006 2 Interce pt: 97. 992 28 Standard Error of Est: 26. 455 85 Strength of Coeff, R^2: 0.0 073 72 Linear Regression Line: Y=97.992-6E(-04)X Range: Ma x: 195 Mi n: 59 Median : 92. 469 5 Mean: 97. 992 26 Mode: 79. 9 Electric AVE 86.475 Gas Average 98.43523 Stand Dev 26.42953 Elect Max 121 Ga s Ma x 195 El ec Mi n 64 ga s mi n 59 gas Upp Q 112.225 elec Upp Q 93.925 gas low Q 79.9 elec low Q 73...
View Full Document

{[ snackBarMessage ]}

### Page1 / 6

Case Study Appendix - degree of freedom = 1.960 CI...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online