Case Study Appendix - degree of freedom = 1.960 CI...

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Case Study Appendix A: B:
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C: D:
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E:
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F: CI = (X-bar apple – X-bar east ) ± t √ (S X-bar apple 2 + S X-bar east 2 ) The formula to find S X-bar is: [S X-bar = (S apple / √ (n) ) 2 [S X-bar apple = 10.0256], [S X-bar east = 14.0810] In order to find t, we must use the t chart. The t value for 95% confidence with an infinite degree of freedom = 1.960. CI = (104.8175 – 87.6751) ± 1.960 √ (10.0256 + 14.0810) CI = (7.5192 , 26.7657) G: CI = (Slope of the regression line, b) ± t of (108-2) (S b ) The formula to find S b is: [S b = (S e /S x √ (n-1)) [S e = 24.44] [S b =.507] In order to find t, we must use the t chart. The t value for 95% confidence with an infinite
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Unformatted text preview: degree of freedom = 1.960. CI = -2.22-1.960*.507<0, -2.22+1.96*.507<0 :CI does not contain null hypothesis, zero. H: Correl. Coeff:-0.0 858 6 Slope:-0.0 006 2 Interce pt: 97. 992 28 Standard Error of Est: 26. 455 85 Strength of Coeff, R^2: 0.0 073 72 Linear Regression Line: Y=97.992-6E(-04)X Range: Ma x: 195 Mi n: 59 Median : 92. 469 5 Mean: 97. 992 26 Mode: 79. 9 Electric AVE 86.475 Gas Average 98.43523 Stand Dev 26.42953 Elect Max 121 Ga s Ma x 195 El ec Mi n 64 ga s mi n 59 gas Upp Q 112.225 elec Upp Q 93.925 gas low Q 79.9 elec low Q 73...
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This note was uploaded on 03/15/2010 for the course QMETH 201 taught by Professor Faaland during the Spring '08 term at University of Washington.

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Case Study Appendix - degree of freedom = 1.960 CI...

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