hw6_solutions - IEOR 130 Methods of Manufacturing...

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1 IEOR 130 Methods of Manufacturing Improvement Solutions to HW #6 Spring 2009, Prof. Leachman 1. (a) M/C A: Avail = 0.896, Util = 0.875, Util of avail = 0.875 / 0.896 = 0.977, OEE = 20/24 = 0.833 M/C B: Avail = 0.938, Util = 0.896, Util of avail = 0.896 / 0.938 = 0.955, OEE = 21/24 = 0.875 M/C C: Avail = 0.979, Util = 0.833, Util of avail = 0.833 / 0.979 = 0.851, OEE = 38*0.5 / 24 = 0.792 M/C D: Avail = 0.875, Util = 0.833, Util of avail = 0.833 / 0.875 = 0.952, OEE = 36*0.5 / 24 = 0.75 (b) Machine A is the bottleneck; reducing its down time will increase fab throughput. Reducing down time at the other machines primarily serves to reduce cycle time. If other machines are upstream from machine A in the process flow, reducing their down time might help to reduce idle time of Machine A, but this is a weaker effect. (c) Machine A is the bottleneck; increasing its rate efficiency will increase fab throughput. Increasing rate efficiency at the other machines primarily serves to reduce cycle time. If
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This note was uploaded on 03/16/2010 for the course ORMS 130 taught by Professor Leachman during the Spring '10 term at University of California, Berkeley.

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hw6_solutions - IEOR 130 Methods of Manufacturing...

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